Question
A and B are travelling towards each other with a speed
of 30 km/hr and 40 km/hr. They started at same time and A covered 35 km less distance than B before meeting B. Find the distance between them before starting.Solution
Here time taken by both A and B is same, so the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 30:40 = 3:4 Let the distance covered by A and B be 3x km and 4x km respectively. According to question, => 4x – 3x = 35 => x = 35 Therefore, distance between them before starting = 4x + 3x = 7x = 245 km
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. p2 – 2p – 15 = 0
II. q2 + 4q – 12 = 0
l. x2 - 16x + 64 = 0
II. y2Â = 64
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 97x² - 436x + 339 = 0
Equation 2: 103y² - 460y + 357 = 0
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
If x² + 2x + 9 = (x – 2) (x – 3), then the resultant equation is:
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