Question
The perimeter of a rectangle is 100% more than perimeter
of a square of side 20 cm. If the length of rectangle is 180% more than side of square then find the difference between the area of square and the area of rectangle.Solution
Perimeter of the square = 4 x 20 = 80 cm Perimeter of the rectangle = 80 x (200/100) = 160 cm Length of the rectangle = 20 x (280/100) = 56 cm Let the breadth of the rectangle be b cm. => 2 x (56 + b) = 160 => b = 80 – 56 => b = 24 cm Required difference = (56 x 24) - (20 x 20) = 944
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
 (1782 ÷ 11.98) ÷ 2.92 × 35.89 + 25% of 541 – 67% of 1299 = ?
16.02% of (189.15 + 210.87) + 9.02³ - (7.95 of 4.98) = ? of (37.95 - 19.89)
You are provided with three sequences below. Determine the values of P, Q, and R, and then identify the relationship among them.<...
25.02% of 460.02+?% of 300.02=295.21
Monthly income of A is Rs. 66000 out of which he spent 18%, 11% and 21% of his total income in rent, medicine and transportation, respectively. Find his...
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
96.03% of √225.02 × 14.98 = ? + 19.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
20.11% of 159.99 + √99.97 ÷ 5.02 = ?
Relevant for Exams:
