Question
Age of ‘A’ after 12 years will be three time of his
age 20 years ago. Eight years hence from now, ratio of ages of ‘A’ and ‘B’ will be 2:3, respectively. If present average age of ‘A’, ‘B’ and ‘C’ is 40 years, then find the present age of ‘C’.Solution
Let present age of ‘A’ be ‘a’ years So, 3(a – 20) = a + 8 Or, 3a – 60 = a + 8 Or, 2a = 68 Or, a = 34 Present age of ‘B’ = 3/2 × {34 + 8} – 8 = 63 – 8 = 55 years Present age of ‘C’ = 40 × 3 – 34 – 55 = 31 years
What will come in place of the question mark (?) in the following series?
15, 26, 39, 56, ?, 98
28, 43, 73, 118, ?, 253
8    12    39      ?       180    216
...226  231   466  ?  5606  28031    Â
48   49    45     54    ?      63      27
...107    157    194    ?     237    247
...-1, 5, 23, 59, ?
51 26 27 ? 86 217.5
- What will come in place of the question mark (?) in the following series?
6, 6, 9, ?, 32, 56 What will come in place of the question mark (?) in the following series?
35, 38, 46, ?, 85, 120