Question
A buffalo alone can plough field ‘A’ in 10 days. A
Bull alone can plough the field ‘A’ in 15 days. Find the number of days taken by 3 bulls and 2 buffalo to together plough field ‘B’ that is 20% larger than field ‘A’?Solution
Let the total work done to plough field ‘A’ = 30 units (LCM of 10 and 15) Then, efficiency of a buffalo = (30/10) = 3 units/day Efficiency of a bull = (30/15) = 2 units/day Total work required to plough field ‘B’ = 30 × 1.20 = 36 units Combined efficiency of 3 bulls and 2 buffalo = 2 × 3 + 3 × 2 = 12 units So, number of days required to plough field ‘B’ = 36/12 = 3 days
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