Question
A buffalo alone can plough field βAβ in 10 days. A
Bull alone can plough the field βAβ in 15 days. Find the number of days taken by 3 bulls and 2 buffalo to together plough field βBβ that is 20% larger than field βAβ?Solution
Let the total work done to plough field βAβ = 30 units (LCM of 10 and 15) Then, efficiency of a buffalo = (30/10) = 3 units/day Efficiency of a bull = (30/15) = 2 units/day Total work required to plough field βBβ = 30 Γ 1.20 = 36 units Combined efficiency of 3 bulls and 2 buffalo = 2 Γ 3 + 3 Γ 2 = 12 units So, number of days required to plough field βBβ = 36/12 = 3 days
More ESIC Part B Questions
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