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Let the cost price and marked price of the article be Rs. 6x and Rs. 11x, respectively Therefore, selling price of the article = 1.50 × 6x = Rs. 9x According to the question, 11x – 9x = 450 Or, x = 450/2 = 225 Therefore, amount by which article is marked up above its cost price = 11x – 6x = 5x = Rs. 1125
I. x2 + 25x + 154 = 0
II. y2 + 27y + 181 = 0
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. 3y2 + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I. x2 = 10
II. y2 - 9y + 20 = 0
...I. x2 – 7x + 12 = 0
II. y2 – 7y + 10 = 0
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. p2 +7p + 10 = 0 II. q2- q – 6 = 0
I. 5x² + 17x + 6 = 0
II. 2y² + 11y + 12 = 0
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