Question
Tap ‘A’ and tap ‘B’ can fill a tank in 40 hours
and 30 hours, respectively. If both taps are opened together, then find the time after which tap ‘A’ must be closed so the whole tank can be filled in 15 hours.Solution
Let total capacity of the tank is 120 litres (LCM of 40 and 30) Quantity of water filled by tap ‘A’ in one hour = 120/40 = 3 litres Quantity of water filled by tap ‘B’ in one hour = 120/30 = 4 litres Let tap ‘A’ is closed after ‘x’ hours So, 7 × x + 4 × (15 – x) = 120 Or, 3x = 60 Or, x = 20 hours
3456 1728 2592 6485 22680 102060
...299, 302, 308, 317, ?, 344
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
230, 34.5, ‘?’, 0.77625
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...There are two series I and II. Logic in both the series are different.
Series l: 3, 12, 28, 53, 89, .
Series II: 259, 270, 283, 300, 319.<...
12, 6, 6, 9, 18, ?
If   314     306      x      269       394    178    1480
Then, 1/3 x + 2x - x = ?
...5     16     ?      66     119      200
...9999 6666 ? 2962.66 1975.11 1316. 74
...
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