Question
The profit earned after selling an article for Rs.1825
is the same as loss incurred after selling the article for Rs.1245. What is the cost price of the article?Solution
Let CP = Rs. x Profit = Rs. y Therefore, x + y = SP => x + y = 1825 ----- (i) When SP = Rs. 1245, the loss = Rs. y Therefore, x – y = 1245 ------- (ii) Solving both the equation, we get => 2x = 3070 => x = Rs. 1535
More ESIC Part B Questions
I. 2x2 + 13x + 21 = 0
II. 3y2 + 34y + 63 = 0
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
The roots of the equations x2 + 16x + 63 = 0
I. 3p² - 17p + 22 = 0
II. 5q² - 21q + 22 = 0
Equation 1: x² - 45x + 500 = 0
Equation 2: y² - 60y + 600 = 0
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
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