A has an amount which is 120% of what B has. What percent of the money should. A give to B so that they have equal amounts?

Solution

ATQ, Let's denote the amount that B has as 'b' . According to the given information, A has an amount that is 120% of what B has, so the amount that A has is 1.2b . Now, we want to find the percentage of money that A should give to B so that they have equal amounts. Let 'x 'be the percentage that A gives to B. Then, A will have  {1.2b - 0.01xb} (A gives x% of 1.2b ) and B will have (b + 0.01xb) . For them to have equal amounts, we set up the equation: 1.2b - 0.01xb = b + 0.01xb Now, solve for : 1.2b - b = 0.01xb + 0.01xb  0.2b = 0.02xb 10 = x Therefore, A should give 10% of the money to B so that they have equal amounts.