Question
40% of the ethanol in a 180-liter mixture of water and
ethanol is ethanol. Determine how much ethanol needs to be added to the mixture in order for it to be 25% less than the water in the final result.Solution
ATQ, Let the quantity of ethanol that must be added in the mixture be 'p' litres. ATQ: 0.4 X 180 + p = 0.75 X 0.6 X 180 Or, 72 + p = 81 So, 'p' = 9 Therefore, quantity of ethanol that must be added = 9 litres
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