Question
A 16% bond with a face value of Rs. 250 is available for
Rs. 200 in the market. The current yield on the bond isSolution
Coupon on the bond = 16% of Rs.250 = Rs.40 Yield = Coupon /MP = 40/200 = 20%
Find the maximum value of 18 sin A + 7 cos A.
- If sin 2a = (3/2), then find the value of (sin a + cos a).
- If X = 15°, find the value of:
sin²(3X) + cos²(4X) - tan²(2X) cot 13Ëš Â
 cot 14˚  ...If 2x = cosec @ and 4/x = cot @ then the value of 2(x ² - 1/x ² ) is
Solve for 0° ≤ θ ≤ 360°:
2 sin²θ + 3 sinθ − 2 = 0
- Simplify the following trigonometric expression:
sin 2A + sin 2B Find the value of the given expression.
2 × (sec 60° – sin 30°)
If cos θ + sin θ = m, sec θ + cosec θ = n then n(m 2 – 1) is equal to?
if x sin 45 Ëš Â = y cosec 30 Ëš Â then find the value ofÂ