We could finish the construction early only if we cut corners .
The correct answer is D
Statement: T < U; W ≤ V = U; I > V; X ≥ U
Conclusion:
I. I > X
II. X ≥ I
Statements:
E = F > Q = A > B; J < Z ≤ A
Conclusions:
I. Q > Z
II. B ˃ J
Statements: A @ Z, Z # L, L % N, N @ U
Conclusions:
I. A @ N
II. Z @ U
III. A # L
Statement: O ≤ Q, Q ≥ A, A > I, I = D
Conclusion: I. Q > D II. A > D
Statements: E * M, M # N, N $ K
Conclusions: a) E * NÂ Â Â Â Â b) M $ K
Statements: S ≥ R > P < Y; R > T ≥ Z; U < T ≥ V
Conclusions:
I. S > V
II. Z ≤ Y
III. Y < Z
Statements: A < B; C = D; B >E ≥ C
Conclusions:
I. A < C
II. E = D
Statement: P < R; P ≥ Q > K; N ≥ O > R
Conclusion:
I. K ≥ R
II. O ≥ P
Statements:          M%G,   G@I,   I$F,    F&O
Conclusions: Â Â Â Â Â Â Â Â Â
 I. I$M  Â
II. I$OÂ Â Â Â...
Statements: J ≥ K ≥ A = M, K ≥ O > W ≥ X
Conclusion:
I. J ≥ X
II. J > X