Question
In the question given below, there is a sentence in which
one part is given in bold. The part given in bold may or may not be grammatically correct. Choose the best alternative among the four given which can replace the part in bold to make the sentence grammatically correct. If the part given in bold is already correct and does not require any replacement, choose option (5), i.e. “No replacement required” as your answer. The RBI has clarified that the bank had failed meeting its priority sector lending target.Solution
“Failed meeting” is incorrect. After "failed," the correct structure is "to + verb" (infinitive). “ Had failed to meet ” is also appropriate in past perfect form because it refers to an action completed before another past event (RBI’s clarification).
How many pairs of letters are there in the word "ANIMATION" which has as many letters between them (both forward and backward) in the word as in the Eng...
- If ‘+’ means ‘-’, ‘×’ means ‘+’, ‘-’ means ‘÷’ and ‘÷’ means ‘×’, then what is the value of the following expression? <...
If,
40 – 14 means 560,
168 + 8 means 21,
26 ÷ 2 means 28,
8 x 7 means 1,
then 410 – 7 x 290 ÷ 350 + 7 x 21 = ?
- Which two signs should be interchanged to correct the given equation?
5 + 3 × 8 – 12 ÷ 4 = 3 In a certain code language, '+' represents ' X ', ' - ' represents '+', '÷' represents '-' and ' X ' represents '÷'. Find out the answer to the follow...
Which two numbers should be interchanged to make the given equation correct?
620 + 75 ÷ 8 × 35 – 44 × 5 + 15 = 583
If '@' means ' X ', '$' means '-', '#' means '÷', and '%' means '+', then what is the value of the expression: [75 % {(169 $ 15) # 11} @ 8]
'!' means '÷', '$' means ' X ', '#' means '+' and '&' means '-' then what would be the value of the expression given below?
Expression: 63 $ ...
If in a certain code language ‘+’ represents ‘×’, ‘–’ represents ‘+’, ‘×’ represents ‘÷’ and ‘÷’ represents ‘–’....
If ‘@’ denotes ‘addition’, ‘%’ denotes ‘multiplication’, ‘&’ denotes ‘subtraction’ and ‘#’ denotes ‘division’, then what...