If ten coins are tossed simultaneously, then the probability of getting at most I head is:

I. 10x² - 11x + 3 = 0

II. 42y² - 23y – 10 = 0

I. x ² + 5 x  + 6 = 0                 

II. y²+ 7 y  + 12= 0

I. 7x² + 27x + 18 = 0

II. 19y² - 27y + 8 = 0

I. 35x² - 51x + 18 = 0

II. 30y² + 17y – 21 = 0

I. 25p + 2(2p² – 1) = 8(p + 5)

II. 8q² + 35q – 78 = 0

I.√(3x-17)+ x=15

II. y + 135/y=24

I. 4p² + 17p + 15 = 0

II. 3q² + 19q + 28 = 0

I. 6x² + 77x + 121 = 0

II. y² + 9y - 22 = 0

I. 9x² + 45x + 26 = 0

II. 7y² – 59y − 36 = 0

I. 4x²+ 25x + 36 =0

II. 2y²+ 5y + 3 = 0