Question
If X and Y are independent random variables and
Var(X)=Var(Y)=4, then find Var(2X-3Y+1)?Solution
Var(2X-3Y+1) = (2)^2*VarX + (3)^2*Var(Y) + Var(1) = 4*4+ 9*4 = 16+36 = 52 Since, variance of constant is 0, so Var (1) is 0.
55 46 60 41 65 36 ?
91   93   97   100   ?   113
12             10            13                18.5                  25.50       �...
80, 255, 624, ?, 2400, 4095
18 Â Â Â Â 32 Â Â Â 50 Â Â Â 72 Â Â Â Â 98 Â Â Â Â ?
100Â Â Â Â 221Â Â Â Â 77Â Â Â Â 245Â Â Â Â 50Â Â Â 275
Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
32, 8, 4, ?, 3, 3.75
30    32    67    206    ?     4166
18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...