Question
For a frequency distribution if Coefficient of variation
is 5, standard deviation is 2 and Karl Pearson’s coefficient of skewness is 0.5, the value of mean and mode areSolution
CV = 5 SD = 2 Sk = 0.5 Also, CV = {SD / Mean} *100 5/100 = 2/Mean Mean = 40 And, Sk = (Mean – Mode) / SD 0.5 = (40 – Mode) / 2 1 = 40 – Mode Mode = 39
More Research Questions
Simplify: 48 ÷ 4 × 2 + 5 × (7 − 3)
560 ÷ 14 × 3 – 25 = ?
- What will come in place of (?) in the given expression.
(0.2 × 0.5) + (0.3 × 0.4) = ? √? × 4 - 374 + 127 + 300 = 117
If (7a + b) : (7a - b) = 7:3, then find the value of a:b?
- Find the simplified form of the following expression:
128 - 85 of 2 + 26 X 4 641.5 + 72 × 8 = ? × 4
What will come in the place of question mark (?) in the given expression?
48 × 1...
55% of ? = 45 + 20 × 6
What will come in place of the question mark (?) in the following expression?
46 – 5² + 8² + 3² = ? × 4
