Question
What will be the probability of losing a game if the
winning probability is 0.3?Solution
Let P(E) is the probability of winning the game, and P(not E) be the probability of not winning the game. P(E) + P(not E) = 1 So, P(not E) = 1 - P(E) Since P(E) = 0.3 P(not E) = 1 - 0.3 P(not E) = 0.7.
What will be the next number in the series?
2,5,11,23,47,?
If 4 10 16 26 x 50
Then find the value of (x² - 1) + ( x² + 1).
...Given below are two numbers series 'I' and 'II' and each series has a wrong (odd one out) number. The number that should come in place of the wrong num...
12 Â Â Â 11 Â Â Â Â 21 Â Â Â Â 62 Â Â Â Â ? Â Â Â Â Â 1234
95 186 376 748 1500 ?
...130Â Â Â Â Â Â Â 155Â Â Â Â Â Â Â 146Â Â Â Â Â Â Â 195 Â Â Â Â Â Â 186 Â Â Â Â Â Â Â ?
...157, 159, 189, 319, ‘?’, 1 407 , 2749 Â
64Â Â Â Â Â Â 66Â Â Â Â Â Â Â 76Â Â Â Â Â Â 126Â Â Â Â Â Â 376Â Â Â Â Â Â Â ?
...83, 88, 86, 91, 89, ?
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...