A man invested a sum of Rs 25,000. He invested some part at 5 % p.a. and remaining at 5.5% p.a. How much money did he invest at 5 % p.a.?

Statement I: The total interest amount paid after 1 year was Rs 1300

Statement II: The interest on the sum invested at 5 % p.a. was twice that on the sum invested at 5.5 % p.a.

Let the first part is Rs x, then remaining part is Rs (25000 - x) From statement I, [(5 ×1 ×x)/100] + [((25,000 -x) ×1 × 5.5)/100] = 1300 -(0.5 x)/100 = - 1375 + 1300 So -0.5x/100 = -75 x = 15,000 From statement II, [(5 ×1 ×x)/100] = 2 [((25,000 -x) ×1 × 5.5)/100] (5 x)/100 = (275000 - 11x)/100 16 x = 275000 x = 17187.50 So answer can be determined by either of statement I or II.

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