What is the order of distance for interatomic forces to be active?
The correct answer is D
2850 ÷ 2.5 - ? × 42 = 300
∛157464 =?
[∛(91125/19683 )- ∛(3375/5832 ) ] × ∛(512/9261) = ? - √(484/3969)
0.3 × 0.2 + 0.4 × 0.3 + ? = 413.18
225÷ 25 x 21 - 30 = ? + √2209 - √7744
The value of [(3√2+2) × (3√2-2)] of 13 + 15 is:
(70% of 480) ÷ 6 + ? = 45% of 3500 + 802+ 272
30% of 8/5 × 5/7 × 2870 =?
12% of 400 - 34 + 65 = ?
44.99% of 499.98 × (3.30/7.40)% of 1399.97 + 10.02 = ?
