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    Question

    What quantity of Urea is required for top dressing of

    two acre of wheat field at a dose  of 60 kg N//ha ?
    A 52 kg Correct Answer Incorrect Answer
    B 105 kg Correct Answer Incorrect Answer
    C 120 kg Correct Answer Incorrect Answer
    D 260 kg Correct Answer Incorrect Answer

    Solution

    Dose of nitrogen: 60 kg N/ha Field area: 2 acres 2 acres = 2 * 0.4047 hectares = 0.8094 hectares Total nitrogen requirement = Dose of nitrogen * Field area = 60 kg N/ha * 0.8094 hectares = 48.564 kg N Quantity of urea required = Total nitrogen requirement / Nitrogen content in urea = 48.564 kg N / 0.46 ≈ 105.558 kg

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