Question
What quantity of Urea is required for top dressing of
two acre of wheat field at a dose of 60 kg N//ha ?Solution
Dose of nitrogen: 60 kg N/ha Field area: 2 acres 2 acres = 2 * 0.4047 hectares = 0.8094 hectares Total nitrogen requirement = Dose of nitrogen * Field area = 60 kg N/ha * 0.8094 hectares = 48.564 kg N Quantity of urea required = Total nitrogen requirement / Nitrogen content in urea = 48.564 kg N / 0.46 ≈ 105.558 kg
  For a perfectly competitive industry , the Marginal cost of producing good X is Rs.10 and that for a Monopoly firm is Rs.12. The demand function fo...
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Q = 10L0.5K0.5
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During which plan, there was focus on indigenous growth?
The fiscal deficit is the difference between the government’s total expenditure and its total receipts excluding ______
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A producer received ₹ 6,000 when the price of a commodity was ₹ 60 per unit. The receipts increased to ₹ 8,400 when the price increased by ₹ 10....
From the following data, find National income.
Which of the following is correct regarding Correlation coefficient?
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