Question
What quantity of Urea is required for top dressing of
two acre of wheat field at a dose of 60 kg N//ha ?Solution
Dose of nitrogen: 60 kg N/ha Field area: 2 acres 2 acres = 2 * 0.4047 hectares = 0.8094 hectares Total nitrogen requirement = Dose of nitrogen * Field area = 60 kg N/ha * 0.8094 hectares = 48.564 kg N Quantity of urea required = Total nitrogen requirement / Nitrogen content in urea = 48.564 kg N / 0.46 ≈ 105.558 kg
23Â Â Â Â 40Â Â Â Â Â Â 67 Â Â Â Â Â Â 104Â Â Â Â Â Â ? Â Â Â Â Â Â 208
...What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
18, 30, 50, 102, 282, ?
- 8, 12, 18, 27, ?
16, 20, 47, 63, 188, ?
- What will come in place of the question mark (?) in the following series?
6, 24, 60, ?, 210, 336 11    16    42    141    ?   2945   17700
...92, 88, 79, ? , 38, 2
What will come in place of the question mark (?) in the following series?
175, 160, 140, 115, ?
45, ?, 84, 114, 151, 195
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