Question
How much area can be irrigated with a flow rate of 30
liters per second for 10 hours a day when irrigation requirement of the 100 days duration crop is 50 cm?Solution
Total discharge during crop period= 30×60×60×10×100/1000 m3 = 108000m3 (1m3=1000 l) Irrigation water require/ ha= 50/100×10000= 5000 m3 Area irrigated= 108000/5000= 21.6 ha
More Agri economics Questions
- What will come in the place of question mark (?) in the given expression?
(106 + 14)/15 = ?/5
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
84367 + 65441 + 32645 – 21145 – 10769 = ?
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
√ (122 + ? + 65) = 14
(82 + 62 ) × 1.25 + 20% of 145 = ? – 40% of 65Â
666(2/3)% of 30 - 116(2/3)% of 90 =?
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
115% of 40 + 3 × 4 = ? × 11 – 8
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