Question
How much area can be irrigated with a flow rate of 30
liters per second for 10 hours a day when irrigation requirement of the 100 days duration crop is 50 cm?Solution
Total discharge during crop period= 30×60×60×10×100/1000 m3 = 108000m3 (1m3=1000 l) Irrigation water require/ ha= 50/100×10000= 5000 m3 Area irrigated= 108000/5000= 21.6 ha
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