Question
Match List I with List II Match the
herbicides in List I with their rate of application in List II List I List II Herbicide Rate of application A. Metolachlor I. 150-200 g/ha B. Tembotrione II. 20 g/ha C. Pyrazosulfuron-ethyl III. 1500 g/ha III. 1500 g/ha D. Oxyfluorfen IV. 120 g/ha Choose the correct answer from the options given below:Solution
Rate of application of Metachlor, Tembotrione, Pyrazosulfuron-ethyland oxyfluorefen is 1500 g/ha, 120 g/ha, 20 g/ha and 150-200 g /ha.
More Agri economics Questions
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
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If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
What will come in the place of question mark (?) in the given expression?
9 (? + 12) = 3 (14 + 17 - 11)
(360 - ?)/(25% of 96) = 13
(16% of 550 – 22% of 700 + 45% of 800) = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
140% of 1270 + 60% of 2085 = 1881 + ‘?’% of 287
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