An 80 gm NaOH is dissolved in 500 ml of water. What is molarity of the solution
Answer: 3 Molecular weight of NaOH= 40 gm Dissolved amount of NaOH=80 gm No of moles= weight of NaOH/Mlecular wt. of NaOH = 80/40=2 Volume of water= 500ml=0.5 litres Molarity= no. of moles of NaOH/Volume of water= 2/0.5=4M
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
(115 × 17 × 3)/(23 × 51) + ?3 = √169
[192 ÷ 6 × 5] ÷ (? + 3) = 20
18 + 28÷ 4 - 14 = ? - 35
...26% of 650 + 15% of 660 – 26% of 450 = ?
(13)2 + 6 × (19)2 – 312 × 4 = ?
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
8888.88 + 888.88 + 88.88 + 8.88 = ? – 0.48
2*1/3 + 22*1/3 + 222*1/3 + 2222*1/2 + 22222*1/2 = ?
