In how many ways can the selection of 4 boys and 3 girls can be made from a group of 6 boys and 6 girls?
Selection of 4 boys from 6 boys = 6C4 = 6!/(4! ×2!) = 15 Selection of 3 girls from 6 girls = 6C3 = 6!/(3! ×3!) = 5 Required number of ways = 15 × 5 = 75
50 ÷ 2.5 × 64 + ? = 1520
25639 – 5252 – 3232 = ?
((67)32 × (67)-18/ ? = (67)⁸
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
7(1/2) – 3(5/6) = ? − 2(7/12)
√(24²+285-8²-172) = ?²
276 ÷ 11.5 + 12 = ? x 3
3 √(432 – 13 + 9 × 32) = ?
1024 ÷ 32 = 2(1/2)×?
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
