Start learning 50% faster. Sign in now
All ox are cattle(A) ⇒ Conversion ⇒ Some cattle are ox(I). Hence conclusion I follows. All bulls are cows(A) ⇒ Conversion ⇒ Some cows are bulls(I). Hence conclusion II follows. No cow is ox(E) + Some ox are buffaloes(I) ⇒ Some buffaloes are not cows(O*). Hence conclusion III does not follow. All bulls are cows(A) + No cow is ox(E) ⇒ No bull is ox(E) ⇒ Convserion ⇒ Some ox are not bull(O). Hence conclusion IV does not follow. ALTERNATE SOLUTION:
Five persons, A, B, C, D, E, are sitting around a circular table facing towards the
centre.
1. A is the neighbour of E and D.
Select the option that is related to the third letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster.
<...Select the number from among the given options that can replace the question mark (?) in the following series.
11, 19, 35, 59, ? , 131
...Select the number from among the given options that can replace the question mark (?) in the following series. 363, 344, 325, 306, ?
Which of the following numbers will replace the question mark (?) in the given series?
8, 14, ? , 44, 68, 98, 134
If in a certain code language 'INTERCITY' is written as 'IXRMTUPEY', then how will 'MACARONIC' be coded in that language?