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All ox are cattle(A) ⇒ Conversion ⇒ Some cattle are ox(I). Hence conclusion I follows. All bulls are cows(A) ⇒ Conversion ⇒ Some cows are bulls(I). Hence conclusion II follows. No cow is ox(E) + Some ox are buffaloes(I) ⇒ Some buffaloes are not cows(O*). Hence conclusion III does not follow. All bulls are cows(A) + No cow is ox(E) ⇒ No bull is ox(E) ⇒ Convserion ⇒ Some ox are not bull(O). Hence conclusion IV does not follow. ALTERNATE SOLUTION:
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