Question
What is the remainder when (q¹⁹ + 1) is divided by (q +
1)?Solution
ATQ;
We know that (aᵐ + bᵐ) is divisible by (a + b) when m is an odd positive number.
Here, m = 19, therefore (q¹⁹ + 1) is divisible by (q + 1).
Therefore, the required remainder will be 0.
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