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      Question

      A series contains thirteen consecutive odd numbers. If the

      average of these numbers is 41, determine the ratio of the first number to the last number in the sequence.
      A 35:37 Correct Answer Incorrect Answer
      B 36:37 Correct Answer Incorrect Answer
      C 25:57 Correct Answer Incorrect Answer
      D 29:53 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the first number of the series be ‘x’.

      2nd number will be = ‘x + 2’

      So, the series becomes:

      x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16, x + 18, x + 20, x + 22, x + 24

      Average of series = (x + x + 24)/2 = x + 12

      ATQ;

      41 = x + 12

      Or, x = 29

      So, the last (13th) number = x + 24 = 29 + 24 = 53

      Required ratio = 29:53

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