Question
‘X’ and ‘Y’ together can complete a task in 18
hours. If ‘Y’ alone takes 45 hours to complete the same task, how long will ‘X’ take to do it alone?Solution
ATQ,
Let the total work = 90 units {LCM (18 and 45)}
Efficiency of ‘X’ and ‘Y’ together = (90/18) = 5 units/hour
Efficiency of ‘Y’ alone = (90/45) = 2 units/hour
Efficiency of ‘X’ alone = (5 – 2) = 3 units/hour
Time taken by ‘X’ to finish the work alone = (90/3) hours = (90/3) × 60 = 1800 minutes
?² = 37% of 800 – 14 × 18+ 5! - 20
If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
(144 ÷ 4)² × (72 ÷ 12)³ = 12 ×? × (25920 ÷10)
3/4 of 2000 + √1024 = ? + 12.5% of 3200
31% of 3300 +659 = ?
√? = 80% of 720 - 22% of 2500
25% of {(5/18) × 2880 + 122 } = ?% of 590
- What will come in place of (?), in the given expression.
75% of 640 – 20% of 150 = ? 1500 × 60% of 25% = ? 2
(〖(0.4)〗^(1/3) × 〖(1/64)〗^(1/4) × 〖16〗^(1/6) × 〖(0.256)〗^(2/3))/(〖(0.16)〗^(2/3) × 4^(-1/2) ×〖1024〗^(-1/4) ) = ?
