Question
If (x – (1/x) = 5√2), then calculate the value of
{(x4 + (1/x4)} ÷ 1351}.Solution
x – 1/x = 5√2
On squaring both sides, we get
(x – 1/x )2 = (5√2)2
Or, x2Â +Â 1/x2Â - 2 = 25 X 2
Or, x2Â +Â 1/ x2Â = 50 + 2
Or, x2Â +Â 1/x2Â = 52
On squaring both sides again, we get
x4Â +Â 1/ x4Â + 2 = 2704
Or, x4Â +Â 1/ x4Â = 2702
So, (x4 + 1/ x4) ÷ 1351= 2702 ÷ 1351 = 2
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
- If the quadratic equation x² + 18x + n = 0 has real and equal roots, what is the value of n?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 27x² - 114x + 99 = 0
Equation 2: 18y² - 70y + 68 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 8x – 3y = 85
II. 4x – 5y = 67
I. 6x2 - 41x+13=0
II. 2y2 - 19y+42=0
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