Question
If 'B' is coded as '4' and 'BALL' is coded as '44', then
how will 'BALLOON' be coded?Solution
The logic followed is:Each letter's positional value in the alphabet is added together and then multiplied by 2. B = 2 × 2 = 4 BALL = (2 + 1 + 12 + 12) × 2 = (27) × 2 = 54 BALLOON = (2 + 1 + 12 + 12 + 15 + 15 + 14) × 2 = 71 × 2 = 142
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