Question
Question: Among 6 trees, A, B, C, D, E and F each having
a different height, which tree is the third tallest? Statement: (I) B is shorter than only D. C is taller than E but shorter than A and F. (II) C is shorter than four other trees. B is taller than A and E but shorter than D. F is not the tallest.ÂSolution
Combining I and II: From I: D > B > ?; C < A/F but > E Let’s try to order: Tallest (1st): D 2nd tallest: B (from I & II) Who is 3rd tallest? Options: A or F. From I: C < A/F → so C < 3rd tallest → 3rd tallest must be A or F . After checking carefully, combining both statements allows us to determine the 3rd tallest uniquely . Answer: Both statements together are sufficient.
From II: D tallest, C fifth, B > A/E, F not tallest
From II: F is not tallest, B > A/E → B second → A < B → A could be 3rd?
Yes, possible: Third tallest = F ?
154 × 7 + 480 × 5 = ?% of 6956
(165 × 12) ÷ 45 + 110 = ? × 2
25% of 300 + √(?) = 35% of 600 - 15% of 300
40 of 30% of 220 = ? + 790
40% of 225 – 25% of 120 = 15% of ?
74% of 2840 + 80% of 1640 - ?= 47²
3(2/3) of 2(5/11) of 5(2/5) of 75 = ?
(11/12) × (18/22) × (4/3) + 3 = ?2
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
263 + 1152 - ? + 577 = 1333