How many numbers are there between 99 and 1000 such that the digit 8 occupies the units place? 

⇒ Number of digit that can occupy hundred's place = 9 (1, 2, 3, 4, 5, 6, 7, 8, 9) {0 not included as it will make the number a two digit number} ⇒ Number of digit that can occupy ten's place = 10 (0, 1, 2, 3, 4, 5, 6, 7, 8, 9) {0 included} ⇒ The number of digits that can occupy one's place = 1 (only 8 can occupy this position as stated in question) ⇒ The total numbers between 99 and 1000 where unit's place is occupied by 8 = 9 × 10 × 1 = 90 ∴ The required result will be 90.