Question
An amount of 62 is divided among A, B and C such that A
gets ₹12 more than B and B gets ₹10 more than C. What is the ratio of their share?Solution
ATQ, Let C’s share = ₹x B gets ₹10 more, so B = ₹(x + 10) A gets ₹12 more than B, so A = ₹(x + 22) Total amount is ₹62, So,(x+22)+(x+10)+x=62 On simplifying, we get: 3x+32=62 3x=30 ⇒ x=10 Now, their shares: C = ₹10, B = ₹20, A = ₹32 Ratio A : B : C = 32:20:10 = 16:10:5 Hence, the ratio of their share is 16:10:5.
1 + 1 + 1/2+ 1/3 + 1/6 + 1/4 is equal to ____
3/7 of 686 + 133(1/3)% of 33 – 69 =?
(30% of 400 - 20% of 540 + 35% of 1000) = ?
20 × 224 ÷ 16 – 50 = ? + 100
...225÷ 25 x 21 - 30 = ? + √2209 - √7744
√2025 + √1024 - √1296 = 20% of ?
(2/5)(32% of 4500 – 440) = ? × 8
140% of 9/8 of ? = 108% of 2800
?% of 18% of 2600 = 234
- Evaluate: 168 ÷ 12 × 5 + 190 – 20% of 450