Total number of couples = 100% So couples having only one child is 20% of 100% = 20/100 x 100 = 20 Remaining 100- 20 = 80 Now couples having two child is 45% of remaining, i.e. 80 x 45% = 80 x 45/100 = 36, Remaining left now = 80% - 36% = 44%.
√11025 x √5625 - (50)² = (?) + (73)²
12% of 152 + 12% of 150 = ? of 5
(64/25)?× (125/512)?-1= 5/8
29% of 400 + 66% of 1100 - 50% of 1200 = ?
((0.1)3+ (1.8)3+ (1.1)3- 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- (...
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...110 ÷ 5.5 + (?)3 ÷ 12 = 20(2/3)
If 32x + 1– 3x= 3x + 3– 32, then values of x are:
[√441 ÷7] × 40% of ? = 500 – 12.5% of 400
