Question
Given below are four combinations [i], [ii], [iii] and
[iv] of five words. In each combination you have to arrange the letters in English alphabetical order from left to right. Then in each combination the first letter from the left end is numbered as I, the second letter from the left end is numbered as II and so on. Hence in each combination I, II, III, IV, and V will denote the position of the letters from the left end. [i] RLWYM [ii] IMPES [iii] NOATR [iv] DPKES From each of the given words, the letters, which are at the same positions are clubbed together. The letters which are at position [I] will form a word if taken in order of combination [i], [ii], [iii], and [iv] respectively and similarly form [I II III IV and V]. Then, how many meaningful words will be formed? TYPE - 7Solution
Arranging the letter in English alphabetical order, we get: [i] RLWYM - LMRWY [ii] IMPES – EIMPS [iii] NOATR – ANORT [iv] DPKES – DEKPS On clubbing together in (I, II, III, IV, and V) from the left end, we get: 
Only I and II will make a meaningful word i.e. ‘LEAF’ and ‘MINE’.
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