Question
Determine the smallest 4-digit number that, when divided
by 15, 24, and 30, leaves a remainder of 5 each time.Solution
Prime factorization of 15 = 3 1 X 5 1 Prime factorization of 24 = 2 3 X 3 1 Prime factorization of 30 = 2 1 X 3 1 X 5 1 LCM of (15, 24, and 30) = 2 3 X 3 1 X 5 1 = 8 X 3 X 5 = 120 Least 4-digit number divisible by 120 = 1,080 So, required number = 1080 + 5 = 1,085
Income of A is twice the income of B. B and A spend 55% and 65% respectively of their incomes. Find the savings of A, if B saves Rs. 18000 in a month.
Find the value of: {(78/4) + (15/6)} ÷ 2 - 6
The following table shows the number of cars sold by a dealership in the first six months of the year.
Train P takes 24 seconds to pass a tree and 34 seconds to pass through a 150-meter-long tunnel. Train Q, which is 440 meters long...
Find the average of the following set of numbers: 13, 42, 22, 35, 68.
Pawan and Bhanu started a business with their investments in the ratio 5:7. After 6 months, Raju joined the business with an inve...
A retailer offers a discount of 20% on a product. If the product’s marked price is ₹500 and the retailer still makes a profit of 12%, find the cost ...
A cube of volume 768 cm³ is molded into a cuboid whose length, width, and height are in the ratio 2: 2: 3. Find the length of the cuboid.
