Question
sin2 7 ° + sin2 8 ° +
sin2 9 ° + sin2 10 ° + ……… + sin2 83 ° = ?Solution
sin2 7 ° + sin2 8 ° + sin2 9 ° + sin2 10 ° + ……… + sin2 83 ° = (sin 2 7 ° + sin2 83 °)+(sin2 8 ° + sin2 82 °) + .…. + (sin2 44 ° + sin2 46 °) + sin2 45 ° = (sin2 7 ° + cos2 7 °)+(sin2 8 °+ cos2 8 °) + .…. + (sin2 44 ° + cos2 44 °)+ sin2 45 °  {As sin (90 ° - θ) = cos θ} = (1)+(1) + .…. upto 38 times + sin2 45 ° { As sin2 θ + cos2 θ= 1} = 38 + sin2 45 °                 = 38 + (1/√2)2 {As sin 45 ° =1/√2 } = 38 + 
 = 38.5
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sin10Ëš x sin20Ëš x sin40Ëš =?Â
2 × Tan 30° / (1 + Tan2 30°) equals:Â
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If X = 15°, find the value of:
sin²(3X) + cos²(4X) - tan²(2X)
