Question
A man observes the top of a tower at an angle of
elevation of 30°. He walks 100 meters closer to the tower, and the angle of elevation becomes 60°. If the height of the tower remains constant, find the initial distance of the man from the base of the tower.Solution
Let the height of the tower be h meters, and the initial distance from the man to the base of the tower be x meters. From the first position: tan 30° = h / x → 1/√3 = h / x x = h√3. From the second position: tan 60° = h / (x - 100) √3 = h / (x - 100). Substitute x = h√3: √3 = h / (h√3 - 100). Cross-multiply: h√3 - 100 = h / √3. 3h - 100√3 = h. 2h = 100√3. h = 50√3. Now, x = h√3 = 50√3 × √3 = 150 m. Answer: b) 150 m
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