Question
If sin A = (4/5), then find the value of {cosec A × cos
A + sec A × tan A}.Solution
Let ABC be a right-angled triangle. Given, in A = 4/5 Or sin A = BC/AC = (4/5) By using Pythagoras theorem, BA ² = AC ² – BC ² = 25 – 16= 9 So, BA = 3units Now, Cosec A × cos A + sec A × tan A =  (AC/BC) ×(AB/AC) + (AC/AB) × (BC/AB)  = (5/4) × (3/5) +(5/3) × (4/3) = (3/4) + (20/9) =107/36
A-5,  A,  35,  52, 78, 115
30, 42, 48, 54, 65, 81, 126
- Find the wrong number in the given number series.
25, 34, 18, 34, 9, 46 Find the wrong number in the given number series.
32, 48, 72, 108, 162, 245
Find the wrong number in the given number series.
1600, 800, 1200, 400, 100 , 12.5
547, 594, 640, 691, 741, 792
Find the wrong number in the given number series.
26, 38, 60, 110, 206, 398
75, 450, 225, 1330, 675, 4050
Find the wrong number in the given number series.
8, 12, 23, 40, 66, 103
62, 79, 98, 119, 142, 165
Relevant for Exams:
