If (5sinx - cosx) = 2√2sinx, then find the value of 'tanx'
(5sinx - cosx) = 2√2sinx Dividing both side with sinx, 5 – cotx = 2√2 cotx = 5 - 2√2 tanx = 1/(5 - 2√2) tanx = (5 + 2√2)/{( 5 - 2√2) × (5 + 2√2)} = (5 + 2√2)/17
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