Question
Calculate the hypotenuse of an isosceles right-angled
triangle where the equal sides are 8√6 cm each.Solution
ATQ, Since ΔABC is an isosceles right-angled triangle, then AC = AB ⇒ AC = AB = 8√6 cm (Given) Now, using the Pythagoras theorem, we get BC² = AC² + AB² ⇒ BC² = AB² + AB² ⇒ BC² = 2AB² ⇒ BC² = 2(8√6)² ⇒ BC² = 2(64 × 6) ⇒ BC² = 768 ⇒ BC = √768 = 16√3 cm Hence, the length of the hypotenuse is 16√3 cm.
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
Â
√(24²+285-8²-172) = ?²
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