Question
In a triangle ABC, the lengths of sides AB, BC, and AC
are 13 cm, 14 cm, and 15 cm, respectively. Find the area of the triangle.Solution
Using Heron's formula: Area = √[s(s - a)(s - b)(s - c)], where s = (a + b + c) / 2 s = (13 + 14 + 15) / 2 = 21 Area = √[21(21 - 13)(21 - 14)(21 - 15)] = √[21 × 8 × 7 × 6] = √7056 = 84 cm²
42, 54, 78, 114, 168, 222
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24, 13, ?, 29, 117, 937
If cos A = 4/5 and A is an acute angle, find the value of 3 tan A + 4 sec A.
