Question
In a triangle ABC, the lengths of sides AB, BC, and AC
are 13 cm, 14 cm, and 15 cm, respectively. Find the area of the triangle.Solution
Using Heron's formula: Area = √[s(s - a)(s - b)(s - c)], where s = (a + b + c) / 2 s = (13 + 14 + 15) / 2 = 21 Area = √[21(21 - 13)(21 - 14)(21 - 15)] = √[21 × 8 × 7 × 6] = √7056 = 84 cm²
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