Question
The corresponding medians of two similar triangles are
12 cm and 15 cm. If the area of the first triangle is 288 cm, then find the area of the second triangleSolution
Let the area of the second triangle = x cm² Then (Area of the first triangle ×) (median of the second triangle) ² = (area of the second triangle) × (median of the first triangle) ² 288 × 225 = x × 144 x = 450cm²
Determine the remainder when equation 4a3Â - 5a2Â + 2a + 1 is divided by (4a - 3) .Â
If -5 ≤ x ≤ 3 and -1 ≤ y ≤ 0, then the minimum value of 2y – 3x is:
Find x, given 5 (√5)x+6 = (√5)2x+7 :
The total number of even factors of 25 × 33 × 52 is:
Solve for x (x > 1):
log₃(x − 1) + log₃(x + 1) = 2
If x3 + y3 + z3 = 3(1 + xyz), P = y + z – x, Q = z + x – y and R = x + y – z, then what is the value of P...
Solve the equation:
3(x − 2) + 4(2x + 1) = 5(2x − 3) + 7
If a3 = 117 + b3 and a = 3 + b, then the value of a + b is:
Which one of the following is the equation for Velocity Time relation?
The value of the expression (1 + sec22° + cot68°)(1 – cosec22° + tan68°) is
