Question
Train A and B can cross a 300 meters long platform in
the same time. The length of Train A is 420 meters and the speed of Train B is 3/2 times the speed of Train A. If Train A crosses a bridge of the same length as of Train B in 60 seconds, then find the time (in seconds) taken by Train B to cross a tunnel 180 m long.Solution
Let speed of train A = 2x meters/second
And speed of train B = 3x meters/second
Let length of train B = y meters ATQ, (y + 300)/3x = (420 + 300)/2x
y + 300 = 1080
y = 780 meters Speed of train A = (420 + 780)/60 = 20 m/sec
Speed of train B = 3/2 × 20 = 30 m/sec Required time = (780 + 180)/30 = 32 sec
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