Question
Train A and B can cross a 300 meters long platform in
the same time. The length of Train A is 420 meters and the speed of Train B is 3/2 times the speed of Train A. If Train A crosses a bridge of the same length as of Train B in 60 seconds, then find the time (in seconds) taken by Train B to cross a tunnel 180 m long.Solution
Let speed of train A = 2x meters/second
And speed of train B = 3x meters/second
Let length of train B = y meters ATQ, (y + 300)/3x = (420 + 300)/2x
y + 300 = 1080
y = 780 meters Speed of train A = (420 + 780)/60 = 20 m/sec
Speed of train B = 3/2 × 20 = 30 m/sec Required time = (780 + 180)/30 = 32 sec
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
- 29.98% of 249.897 = ?² – (4.98)²
What is the area (in cm²) of a square inscribed in a circle with a radius of 10√2 cm?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
29.99...
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)
