Question
Two trains ‘T4’ and ‘U4’ of lengths 360 metres and 540 metres respectively are travelling towards each other. Ratio of speed of ‘T4’ to ‘U4’ is 2:3. If the trains take 36 seconds to cross each other from the time they meet, then find the average of speeds (in km/h) of trains ‘T4’ and ‘U4’.
Solution
Let the speed of ‘T4’ and ‘U4’ be ‘2y’ and ‘3y’ m/s respectively.
Relative speed = 2y + 3y = 5y m/s
ATQ,
5y × 36 = 360 + 540
⇒ 180y = 900
⇒ y = 5
Therefore, required average = (2y + 3y) ÷ 2 = 2.5y
= 2.5 × 5 = 12.5 m/s = 12.5 × (18/5) = 45 km/h
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