Question
Train 'A' having a speed of 18 m/s can cross a man in 10
seconds. The length of train 'B' is 120 metres more than the length of 'A'. If the speed of 'B' is 42 m/sec and both trains are travelling towards each other, then find the time taken by them to cross each other.Solution
Length of train 'A' = 18 × 10 = 180 metres
Length of train 'B' = 180 + 120 = 300 metres
Relative speed = 18 + 42 = 60 m/sec
Required time = (180 + 300) ÷ 60 = 480 ÷ 60 = 8.0 seconds
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