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      Question

      Train 'A' having a speed of 18 m/s can cross a man in 10

      seconds. The length of train 'B' is 120 metres more than the length of 'A'. If the speed of 'B' is 42 m/sec and both trains are travelling towards each other, then find the time taken by them to cross each other.
      A 7.0 seconds Correct Answer Incorrect Answer
      B 7.5 seconds Correct Answer Incorrect Answer
      C 8.0 seconds Correct Answer Incorrect Answer
      D 8.5 seconds Correct Answer Incorrect Answer
      E 9.0 seconds Correct Answer Incorrect Answer

      Solution

      Length of train 'A' = 18 × 10 = 180 metres
      Length of train 'B' = 180 + 120 = 300 metres
      Relative speed = 18 + 42 = 60 m/sec
      Required time = (180 + 300) ÷ 60 = 480 ÷ 60 = 8.0 seconds

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