Question
A pedestrian walking at 6 km/h is overtaken by a train
running at three times the speed of the pedestrian. If it takes 9 seconds to cross him, find the train’s length.Solution
ATQ,
Speed of the pedestrian = 6 × (5/18) = 1.67 m/s
So, speed of the train = 1.67 × 3 = 5.01 m/s
Let the length of the train be 'x' metres
ATQ:
x / (5.01 - 1.67) = 9
So, x = 30
Length of the train = 30 metres
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