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ATQ;
Let length of the train be ‘L’ metres
ATQ,
(L/30) = {(L + 250)/40}
Or, 40L = 30L + 7500
Or, 10L = 7500
Or, L = 750
So, length of the train = 750 metres
Therefore, speed of the train = (750/30) = 25 m/s
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