Question
Train 'A' travels at a speed of 54 km/hr and passes a
stationary pole in 12.4 seconds. How long will it take for Train 'A' to completely pass Train 'B', given that Train 'B' is 48 meters longer than Train 'A' and is traveling at a speed that is one-third faster than Train 'A'? Both trains are moving in opposite directions.Solution
Speed of train βAβ = 54 Γ (5/18) = 15 m/sec Therefore, length of train βAβ = 15 Γ 12.4 = 186 metres Length of train βBβ = 186 + 48 = 234 metres Speed of train βBβ = 15 + (15/3) = 20 m/sec Required time taken = (234 + 186)/(15 + 20) = 12 seconds
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