Question
A train can cross a pole and a platform of 300 meters
long in 8 sec and 20 sec respectively. Find the time taken by the train to cross another platform having length 250 meters.Solution
Let the length of the train be ‘x’ meters. According to question, => x/8 = (x + 300)/20 => 20x = 8x + 2400 => x = 200 The speed of the train = 200/8 = 25 m/s Required time taken by train to cross another platform = (200 + 250)/25 = 18 sec
More Trains Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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