Question
Two trains A and B, were proceeding in the same
direction on parallel tracks at 98 km/hr and 170 km/hr respectively. A man noticed that it took exactly 15 seconds for the faster train to pass by him. What is the length of the faster train?Solution
Relative speed = (170 – 98) km/hr = 72 km/hr => 72 × (5/18) = 20 m/sec Length of the faster train = 20 × 15 = 300 m
Find the value of sin(θ) if 2sinθ = tanθ, for 0 < θ < 90°.
The value of (3tan10°-tan³10°)/(1-3tan²10°) is equal to
- Find the value of sin²18° + sin²72° + cos²63° + cos²27°.
- Find the maximum value of (15sin A + 12cos A).
∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
If cosec2A = (sin60o + tan45o X sec245o), then find the value of sin2A.
If √3 tan x = 3, then the value of x:
If sin5A = cos(2A+20°), then what is the value of A? Given that 5A is an acute angle.
